Question

4x2 + 4x = 1
Решите пожалуйста

Answer 1

$4x^2+4x=1\\\\4x^2+4x-1=0\\\\(2x)^2+4x+1-2=0\\\\(2x+1)^2=2\\\\2x+1=\pm\sqrt2\\\\\left[\begin{array}{lcl}2x+1=-\sqrt{2}\\2x+1=\sqrt2\end{array}\right\ =>\ \ \left[\begin{array}{lcl}x_1=\dfrac{-\sqrt2-1}2\\\\x_2=\dfrac{\sqrt2-1}2\end{array}$