Предмет: Физика, автор: 62bz9pxuzj

Определите коофицент жёсткости пружины на которой подвешен груз весом 7н если это пружина удлинилась на 4см

Ответы

Автор ответа: fatt52

0

Ответ:

175 Н/м

Объяснение:

F=7 H x=0.04 м k=?

===

F=k*x

k=F/x=7/0.04=175 Н/м

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