Question

Помогите пожалуйста решить

Answer 1

$\displaystyle\bf \frac{x^{2} }{x-1}-\frac{3x}{1-x} = \frac{4}{x-1} \\\\\\ \frac{x^{2} }{x-1}+\frac{3x}{x-1} - \frac{4}{x-1} =0\\\\\\ \frac{x^{2} +3x-4}{x-1} =0\\\\\\ \left \{ {{x^{2} +3x-4=0} \atop {x-1\neq 0}} \right.\\\\\\ \left \{ {{\left[\begin{array}{ccc}x_{1} =-4\\x_{2} =1\end{array}\right } \atop {x\neq 1}} \right. \\\\\\ Otvet:-4$