Question

2
a) 9a² + 6аc + c2;
B) 4m² + 4m + 1;
2

Answer 1

Ответ:

$\boxed{\ a^2\pm 2ab+b^2=(a\pm b)^2\ }\\\\\\a)\ \ \ 9a^2+6ac+c^2=(3a)^2+2\cdot (3a)\cdot c+c^2=(3a+c)^2\\\\\\b)\ \ 4m^2+4m+1=(2m)^2+2\cdot (2m)\cdot 1+1^2=(4m+1)^2$