Question

помогите з алгеброй​

Answer 1

Ответ:

$x^2-\underbrace{(1,2x-3)(3+1,2x)}=0,2x\, (1,5-2,2x)\ \ ,\ \ \ \boxed{\ (a-b)(a+b)=a^2-b^2\ }\\\\x^2-((1,2x)^2-3^2)=0,3x-0,44x^2\\\\x^2-1,44x^2+9=0,3x-0,44x^2\\\\x^2+9=0,3x+x^2\\\\0,3x=9\\\\x=30$