Question

СРОЧНО ПОМОГИТЕ ПОЖАЛУЙСТА ​

Answer 1

${}\ \ \ \dfrac{*\ -50u^2h^4+75uh^5}{5uh^3}=4u^2\ -\ *\ +\ *\\\\\\\dfrac{*\ -50u^2h^4+75uh^5}{5uh^3}=\dfrac{*}{5uh^3}-\dfrac{50u^2h^4}{5uh^3}+\dfrac{75uh^5}{5uh^3}\\\\\\\dfrac{*\ -50u^2h^4+75uh^5}{5uh^3}=\dfrac{*}{5uh^3}-10uh+15h^2\\\\\\\dfrac{*}{5uh^3}=4u^2\ \ \ \Rightarrow \ \ \ *\ =5uh^3\cdot 4u^2\ \ ,\ \ \ *\ =20u^3h^3\\\\\\Otvet:\ \ \dfrac{20u^3h^3 -50u^2h^4+75uh^5}{5uh^3}=4u^2-10uh+15h^2$

$\boxed{\ \dfrac{a\pm b}{c}=\dfrac{a}{c}\pm \dfrac{b}{c}\ \ \ ,\ \ \ \dfrac{a^{n}}{a^{k}}=a^{n-k}\ }$