Question

Представь квадрат двучлена в виде многочлена (5/6-1/4u^7) ^2​

Answer 1

$( \frac{5}{6} - \frac{1}{4} {u}^{7}) ^{2} = \frac{25}{36} - \frac{5}{12} {u}^{7} + \frac{1}{16} {u}^{14}$

Answer 2

Ответ:

${}\qquad \quad \boxed{\ (a-b)^2=a^2-2ab+b^2\ }\\\\\\\displaystyle \Big(\frac{5}{6}-\frac{1}{4}\, u^7\Big)^2=\Big(\frac{5}{6}\Big)^2-2\cdot \frac{5}{6}\cdot \frac{1}{4}\, u^7+\Big(\frac{1}{4}\, u^7\Big)^2=\frac{25}{36}-\frac{5}{12}\, u^7+\frac{1}{16}\, u^{14}$