Question

Решить систему уравнений на фото

Answer 1

$\displaystyle \left \{ {{3x^2-2y^2=4} \atop {4x+3y=2}} \right.\\ \left \{ {{3x^2-2y^2=4} \atop {x=\frac{1}{2}-\frac{3}{4}y }} \right. \\ 3(\frac{1}{2}-\frac{3}{4}y)^2-2y^2=4\\ y=-\frac{26}{5},y=-2\\ x=\frac{1}{2}-\frac{3}{4}*(-\frac{26}{5}) \rightarrow x=\frac{22}{5}\\ x=\frac{1}{2}-\frac{3}{4}*(-2) \rightarrow x=2\\ (x_1,y_1)=(\frac{22}{5},-\frac{26}{5})\\ (x_2,y_2)=(2,-2)$