Question

помогите решить пожалуйста

Answer 1

1) y1=2-1=1
y2=8-2=6
y3=18-3=15
y4=32-4=28
y5=50-5=45
2)y'=$sqrt{x} *4 x^{3}+ frac{ x^{4}+2}{2 sqrt{x} }$
$y'= frac{ frac{-(8-3x)}{ sqrt{x} }+6[tex]-sin2x+ int{ (frac{cos4x}{2}+ frac{1}{2} ) } , dx = frac{x}{4} -sin2x+ frac{x}{2} + frac{sin4x}{8} +c= frac{3x}{4} -sin2x+$x sqrt{x} }{(8-3x)^2} = frac{-8+3x+6 x^{2} }{ sqrt{x} (8-3x)^2} [/tex]
3)$lim_{x to 0} frac{ x^{2} (sqrt{ x^{2} +1} +1)}{ x^{2} } = lim_{xto 0} sqrt{ x^{2} +1} +1=1+1=2$
$lim_{x to 0} frac{xcosx}{sinx} =1*1=1$
4)$int {(sin^2x)^2} , dx = int{( frac{-cos2x}{2} + frac{1}{2} )^2} , dx = int ({ frac{1}{4} } - frac{cos2x}{2}+ frac{cos^22x}{4} ) , dx = frac{x}{4} -$

Answer 2

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