Question

помогите пожалуйста ​

Answer 1

${9a}^{2} + 6ac + {c}^{2} = {(3a + c)}^{2} \\ {x}^{4} - {10x}^{2} + 25 = {( {x}^{2} - 5) }^{2} \\ {4m}^{2} + 4m + 1 = ({2m + 1)}^{2} \\ {b}^{4} - {6b}^{2} + 9 = {( {b}^{2} - 3)}^{2}$