Question

Срочно номер 3 (в)решите прошууу даю 50 баллов

Answer 1

$\displaystyle\bf 1)\\P(x)=5x^{2} -11-7x^{2}-8x+1 1+3x=\\\\=\underbrace{(5x^{2} -7x^{2} )}_{-2x^{2} }-\underbrace{(8x-3x)}_{5x}-\underbrace{(11-11)}_{0}=-2x^{2} -5x\\\\\\2)\\-2x^{2} -5x=0\\\\x^{2} +2,5x=0\\\\x(x+2,5)=0\\\\\\\left[\begin{array}{ccc}x=0\\x+2,5=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =0\\x_{2}=-2,5 \end{array}\right\\\\\\Otvet:0 \ ; \ -2,5$