Предмет: Химия, автор: Arlong

Какие продукты получаются в результате электролиза Pb(CH3COO)2?

Приложения:

Ответы

Автор ответа: DK954

Решение:

Pb(CH₃COO)₂ (раст.) ⇄ Pb²⁺ + 2CH₃COO⁻

Kt⁻ : Pb²⁺ + 2e⁻ → Pb⁰ | 2 | 4 | | 1 | - окислитель

2H₂O + 2e⁻ → H₂↑ + 2OH⁻ | 2 | | 4 | |

An⁺ : 2CH₃COO⁻ - 2e⁻ → C₂H₆ + 2CO₂ | 2 | 2 | | 2 | - восстановитель

H₂O | | | | |

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Pb²⁺ + 2H₂O + 2CH₃COO⁻ → Pb + H₂↑ + 2OH⁻ + 2C₂H₆ + 4CO₂↑

Pb²⁺ + 2CH₃COO⁻ + 2H₂O → Pb + H₂↑ + 2OH⁻ + Pb²⁺ + 2C₂H₆ + 4CO₂↑

В итоге получаем:

2Pb(CH₃COO)₂ + 2H₂O → Pb + H₂↑ + Pb(OH)₂↓ + 2C₂H₆ + 4CO₂↑

Решено от : $DK954$

Arlong: можешь скинуть свой контакт?

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