Question

Помогите решить пожалуйста это дроби

Answer 1

Ответ:

Пошаговое объяснение:

а. 4:4/3=4×3/4=3

7: 7/3=7×3/7=3

3+3=6

b. 29/7:29/8=29/7×8/29=8/7=1 1/7

8 1/7-1 1/7=7

с. 12 2/5-6 1/5=6 1/5

31/5:31/4=31/5×4/31=4/5

Answer 2

$a)~4:1\dfrac{1}{3}+7:2\dfrac{1}{3}=4:\dfrac{1\cdot3+1}{3}+7:\dfrac{2\cdot3+1}{3}=\\\\\\=4:\dfrac{4}{3}+7:\dfrac{7}{3}=4\cdot\dfrac{3}{4}+7\cdot\dfrac{3}{7}=3+3=6\\\\\\b)~8\dfrac{1}{7}-4\dfrac{1}{7}:3\dfrac{5}{8}=\dfrac{8\cdot7+1}{7}-\dfrac{4\cdot7+1}{7}:\dfrac{3\cdot8+5}{8}=\\\\\\=\dfrac{57}{7}-\dfrac{29}{7}:\dfrac{29}{8}=\dfrac{57}{7}-\dfrac{29}{7}\cdot\dfrac{8}{29}=\dfrac{57}{7}-\dfrac{8}{7}=\dfrac{57-8}{7}=\dfrac{49}{7}=7$

$c)~\bigg(12\dfrac{2}{5}-6\dfrac{1}{5}\bigg):7\dfrac{3}{4}=\bigg(\dfrac{12\cdot5+2}{5}-\dfrac{6\cdot5+1}{5}\bigg):\dfrac{7\cdot4+3}{4}=\\\\\\=\bigg(\dfrac{62}{5}-\dfrac{31}{5}\bigg):\dfrac{31}{4}=\dfrac{62-31}{5}:\dfrac{31}{4}=\dfrac{31}{5}\cdot\dfrac{4}{31}=\dfrac{4}{5}$