Question

Решите систему уравнений ‼️
x^2+9x+y^2=5
x^2+9x-y^2=-21

Answer 1

вот так
ответ
вььвбвбв

Answer 2

$\left \{ {{x^2+9x+y^2=5} \atop {x^2+9x-y^2=-21}} \right.\\\left \{ {{y^2=5-x^2-9x} \atop {x^2+9x-y^2=-21}} \right.\\x^2+9x-(5-x^2-9x)=-21\\x=-8\\x=-1\\y^2=5-(-8)^2-9\cdot(-8)\\y^2=5-(-1)^2-9\cdot(-1)\\y=-\sqrt{13}\\y=\sqrt{13}\\y=-\sqrt{13}\\y=\sqrt{13}\\(x_1,y_1)=(-8,-\sqrt{13})\\(x_2,y_2)=(-8,\sqrt{13})\\(x_3,y_3)=(-1,-\sqrt{13})\\(x_4,y_4)=(-1,\sqrt{13})\\ \left \{ {{(-8)^2+9\cdot(-8)+(-\sqrt{13})^2=5} \atop {(-8)^2+9\cdot(-8)-(-\sqrt{13})^2=-21}} \right.$

$\left \{ {{(-8)^2+9\cdot(-8)+\sqrt{13}^2=5} \atop {(-8)^2+9\cdot(-8)-\sqrt{13}^2=-21}}\right.\\\left \{ {{(-1)^2+9\cdot(-1)+(-\sqrt{13})^2=5} \atop {(-1)^2+9\cdot(-1)-(-\sqrt{13})^2=-21 }} \right. \\ \left \{ {{(-1)^2+9\cdot(-1)+\sqrt{13}^2=5 } \atop {(-1)^2+9\cdot(-1)-\sqrt{13}^2=-21}} \right. \\ \left \{ {{5=5} \atop {-21=-21}} \right. \\ \left \{ {{5=5} \atop {-21=-21}} \right. \\ \left \{ {{5=5} \atop {-21=-21}} \right. \\ \left \{ {{5=5} \atop {-21=-21}} \right. \\ (x_1,y_1)=(-8,-\sqrt{13})$

$(x_2,y_2)=(-8,\sqrt{13})\\(x_3,y_3)=(-1,-\sqrt{13})\\(x_4,y_4)=(-1,\sqrt{13})$