Question

Помогите с алгеброй пж

Answer 1

а) a² + (3a - b)² =

= a² + ((3a)² - 2 · 3ab + b²) =

= a² + 9a² - 6ab + b² =

= 10a² - 6ab + b²;

б) 9p² - (q - 3p)² =

= 9p² - (q² - 2 · 3pq + (3p)²) =

= 9p² - (q² - 6pq + 9p²) =

= 9p² - q² + 6pq - 9p² =

= - q² + 6pq.

а) (a - 4)² + a(a + 8) =

= a² - 2 · 4a + 4² + a² + 8a =

= a² - 8a + 16 + a² + 8a =

= 2a² + 16;

б) (x - 7)x + (x + 3)² =

= x² - 7x + (x² + 2 · 3x + 3²) =

= x² - 7x + x² + 6x + 9 =

= 2x² - x + 9.