Предмет: Алгебра, автор: vadimmirpocaev

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Докажите тождество:

Приложения:

Ответы

Автор ответа: sonealya
2

Доказать тождество = доказать, что обе части тождества (до знака "=" и после знака "=") равны. Для этого обе части нужно упростить.

2\frac{2}{7}a-1\frac{4}{14}(a-5b-2b)-9b=(\frac{1}{4}+0,75)a\\\\2\frac{2}{7}a-1\frac{2}{7}(a-7b)-9b=(\frac{1}{4}+\frac{3}{4})a\\\\2\frac{2}{7}a-1\frac{2}{7}a+1\frac{2}{7}*7b-9b=1a\\\\a+\frac{9}{7}*7b-9b=a\\\\a+9b-9b=a\\\\a=a

Тождество доказано.

Автор ответа: Zombynella
0

Ответ:

В решении.

Объяснение:

Докажите тождество:

2 2/7 а - 1 4/14(а - 5b - 2b) - 9b = (1/4 + 0,75)a;

1) Преобразовать левую часть:

16а/7 - 9/7(а - 7b) - 9b =

= 16a/7 - 9a/7 + 9b - 9b =

= 16a/7 - 9a/7 = 7a/7 = a;

2) Преобразовать правую часть:

(1/4 + 0,75)a = (0,25 + 0,75)а = 1*а = а;

3) а = а, тождество доказано.

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