Question

(-12/24+11/10)-(-4/2)-(-5/2) пж помоги​

Answer 1

Ответ:

1)    $(-\frac{12}{24})+(-\frac{11}{10})-(-\frac{4}{2})-(-\frac{5}{2})= -\frac{12}{24}-\frac{11}{10}+\frac{4}{2}+\frac{5}{2}= -\frac{1}{2}-\frac{11}{10}+\frac{9}{2}= \frac{-1+9}{2} -\frac{11}{10}=\\\\=\frac{8}{2}-\frac{11}{10} =4-\frac{11}{10}=\frac{4*10-11}{10} =\frac{40-11}{10}= \frac{29}{10} =2\frac{9}{10}.$

Здесь ответ можно записать как:    $\frac{29}{10}$   или   $2\frac{9}{10}$   или   $2,9.$

2)    $(-\frac{38}{12})-(-\frac{30}{12})-\frac{5}{2}+(-\frac{7}{2})= -\frac{38}{12}+\frac{30}{12}-\frac{5}{2}-\frac{7}{2}= -\frac{38}{12}+\frac{5}{2}-\frac{5}{2}-\frac{7}{2}= -\frac{38}{12}+0-\frac{7}{2}= \\\\= -\frac{38}{12}-\frac{7}{2}= -\frac{19}{6}-\frac{7}{2}=-\frac{19+7*3}{6} =-\frac{19+21}{6} =-\frac{40}{6} =-\frac{20}{3}=-6\frac{2}{3}.$

3)    $(-\frac{80}{12})-(-\frac{48}{11})-(-\frac{3}{2})+(-\frac{6}{3})=-\frac{80}{12}+\frac{48}{11}+\frac{3}{2}-\frac{6}{3}= -\frac{20}{3}+\frac{48}{11}+\frac{3}{2}-\frac{2}{1} = \\\\= \frac{-20*22+48*6+3*33-2*66}{66} =\frac{-440+288+99-132}{66} =\frac{-152+(-33)}{66} =\frac{-185}{66} =-\frac{185}{66} =-2\frac{53}{66}.$