Question

(х-2) (2х+3) =2х -4х

Answer 1

(х-2) (2х+3) =2х-4х

2х²+3х-4х-6=-2х

2х²-х-6+2х=0

2х²+х-6=0

D=1²-4×2×(-6)=1+48=49

x1,2 = -1±7/4, х1 = -2, х2 = 1,5

Answer 2

$\displaystyle (x-2)(2x+3)=2x-4x\\2x^2+3x-4x-6=-2x\\2x^2-x-6=-2x\\2x^2-x-6+2x=0\\2x^2+x-6=0\\2x^2+4x-3x-6=0\\2x(x+2)-3(x+2)=0\\(x+2)(2x-3)=0\\x+2=0,2x-3=0\\\\x_1=-2,x_2=\frac{3}{2}=1,5$