Question

Терміново! Бажано фото з розв'язанням.​

Answer 1

Объяснение:

все описано в картинке.

Answer 2

$\displaystyle 1)2x^2+3x+1<0\\2x^2+2x+x+1<0\\2x(x+1)+x+1<0\\(x+1)(2x+1)<0\\\\\left \{ {{x+1<0} \atop {2x+1>0}} \right.=\left \{ {{x<-1} \atop {x>-\frac{1}{2} }} \right. =x \in \phi\\\\\left \{ {{x+1>0} \atop {2x+1<0}} \right.=\left \{ {{x>-1} \atop {x<-\frac{1}{2} }} \right. =x \in (-1, -\frac{1}{2})\\\\x \in (-1,-\frac{1}{2}\\\\2)\frac{x+5}{x-3}>0\\\\\left \{ {{x+5>0} \atop {x-3>0}} \right. \\\\\left \{ {{x+5<0} \atop {x-3<0}} \right.\\ \\ x\in (- \infty,-5) \cup(3,+ \infty)$