Question

Помогите пожалуйста​

Answer 1

$\displaystyle\left \{ {{(x-8)(y-6)=0} \atop {\frac{y-2}{x+y-10}=4 }} \right.\\\\\left \{ {{(x-8)(y-6)=0} \atop {y-2=4x+4y-40}} \right.\\\\\left \{ {{(x-8)(y-6)=0} \atop {x=-\frac{3}{4}y+\frac{19}{2} }} \right.\\\\(-\frac{3}{4}y+\frac{19}{2}-8)(y-6)=0\\y=2,y=6\\\\x=-\frac{3}{4}*2+\frac{19}{2},x=-\frac{3}{4}*6+\frac{19}{2}\\\\x=8,x=5\\(x_1,y_1)=(8,2),(x_2,y_2)=(5,6)$