Question

очень надо решить задачи! пж​

Answer 1

Ответ:

10. Т.к ∆ABC~∆A1B1C1, то AB/A1B1 = √(SABC/SA1B1C1) = k

4/x = √(32/50)

16/x² = 32/50

32x² = 16•50

2x² = 50

x² = 25.

x = 5.

11. Т.к. ∆MNT~∆M1N1T1, то k = x/9 = √(75/225)

x/9 = √(1/3)

x²/81 = 1/3

x² = 27

x =