Question

решите уравнение дам 10 балов

Answer 1

$\displaystyle 1)\frac{5x-4}{2}=\frac{16x+1}{7}\\\\7(5x-4)=2(16x+1)\\35x-28=32x+2\\35x-32x=2+28\\3x=30\\x=10\\\\2)\frac{4y+33}{3}=\frac{17+y}{2}\\\\2(4y+33)=3(17+y)\\8y+66=51+3y\\8y-3y=51-66\\5y=-15\\y=-3$