Question

Решите неравенство.
Помогите пожалуйста. Дам: 20-25 баллов​

Answer 1

Ответ:

$\displaystyle sin\Big(5x-\frac{\pi}{3}\Bug)<\frac{\sqrt3}{2}\\\\\\-\frac{4\pi}{3}+2\pi n<5x-\frac{\pi}{3}<\frac{\pi }{3}+2\pi n\ \ ,\ n\in Z\\\\\\-\pi +2\pi n<5x<\frac{2\pi }{3}+2\pi n\ \ ,\ n\in Z\\\\\\-\frac{\pi }{5}+\frac{2\pi n}{5}<5x<\frac{2\pi }{15}+\frac{2\pi n}{5}\ \ ,\ n\in Z\\\\\\x\in \Big(-\frac{\pi }{5}+\frac{2\pi n}{5}\ ;\ \frac{2\pi }{15}+\frac{2\pi n}{5}\ \Big)\ \ ,\ n\in Z$