Question

алгебра 7 класс. помогите​

Answer 1

$\displaystyle 1)\frac{3}{8}m^5(2\frac{1}{3}mn^5)^0*\frac{5}{3}m=\frac{1}{8}m^5*1*5m=\frac{5}{8}m^6=0,625m^6\\\\2)(2\frac{1}{3}a^2b)^2(-\frac{9}{49}ab^2c)(-4ab^2)^2=(2\frac{1}{3}a^2b^2)(-\frac{9}{49}ab^2c)(4ab^2)^2=-(\frac{7}{3}a^2b)^2*\frac{9}{49}ab^2c*\\\\16a^2b^4=-\frac{49}{9}a^4b^2*\frac{9}{49}ab^2c*16a^2b^4=-a^4b^2ab^2c*16a^2b^4=-16a^7b^8c$