Question

Сократите дробь
x^2-3x/2x^2-8x+6

Answer 1

$\frac{x { }^{2} - 3x }{2 {x}^{2} - 8x + 6 } = \frac{x(x - 3)}{2(x {}^{2} - x - 3x + 3) } = \frac{x(x - 3)}{2(x \times (x - 1) - 3 \times (x - 1))} = \frac{x(x - 3)}{2(x - 1)(x - 3)} sokrashaem \: x - 3 = \frac{x}{2(x - 1)} = \frac{x}{2x - 2}$