Question

сборник 8 класс номер 173!!!пжпжпжжп

Answer 1

Ответ.

$\displaystyle 3)\ \ \frac{x^2-2x+1}{25+10x+x^2}=\frac{(x-1)^2}{(x+5)^2}\\\\\\x=0:\ \frac{(0-1(^2}{(0+5)^2}=\frac{1}{25}\\\\t=1:\ \frac{0}{36}=0\\\\t=2:\ \frac{1}{7^2}=\frac{1}{49}\\\\t=5:\ \frac{4^2}{10^2}=\frac{16}{100}=\frac{4}{25}$

$\displaystyle 4)\ \ \frac{u^2-12u+36}{4+4u+u^2}=\frac{(u-6)^2}{(u+2)^2}\\\\\\u=0:\ \frac{6^2}{2^2}=9\\\\u=1:\ \frac{5^2}{3^2}=\frac{25}{9}\\\\u=2:\ \frac{4^2}{4^2}=1\\\\u=6:\ \frac{0}{8^2}=0$