Question

Решите неравенство $\sqrt{3x+2} \ \textless \ 1$

Answer 1

Надеюсь правильно)))))

Answer 2

$\displaystyle \sqrt{3x+2}<1,x\geq -\frac{2}{3}\\\\3x+2<1\\3x<1-2\\3x<-1\\\\x<-\frac{1}{3} \\\\x \in [-\frac{2}{3},-\frac{1}{3})$