Question

решите уравнение х² - 4|х| + 3 = 0​

Answer 1

$\displaystyle\bf\\x^{2} -4|x|+3=0\\\\x^{2} =|x|^{2} \\\\|x|^{2} -4|x|+3=0\\\\|x|=m \ \ ; \ \ m\geq 0\\\\m^{2} -4m+3=0\\\\Teorema \ Vieta:\\\\m_{1} =1\\\\m_{2} =3\\\\1)\\\\|x|=1\\\\x_{1} =-1 \ \ ; \ \ x_{2} =1\\\\2)\\\\|x|=3\\\\x_{3} =-3 \ \ ; \ \ x_{4} =3\\\\Otvet:-1 \ ; \ 1 \ ; \ -3 \ ; \ 3$