Question

HELP ME! Please! HELP!

Answer 1

$log5x<2$

$log(5x)=2$

$5x=e^{2}$

$x^{1}=\frac{e^{2} }{5}$

$x_{0}=x_{1}-\frac{1}{10}$

$-\frac{1}{10}+\frac{e^{2} }{5}$

$log(5(-\frac{1}{10}+\frac{e^{2} }{5}))<2$

$x<\frac{e^{2} }{5}$