Question

помогите пожалуйста ​

Answer 1

$\displaystyle \sqrt{x^2+2x+10}=2x-1\\x^2+2x+10=4x^2-4x+1\\x^2+2x+10-4x^2+4x-1=0\\-3x^2+6x+9=0\\x^2-2x-3=0\\x^2+x-3x-3=0\\x(x+1)-3(x+1)=0\\(x+1)(x-3)=0\\x+1=0,x-3=0\\x=-1,x=3\\\sqrt{(-1)^2+2*(-1)+10}=2*(-1)-1, \sqrt{3^2+2*3+10}=2*3-1\\x\neq -1,x=3\\x=3$