Предмет: Математика, автор: igoreik48

Помогите найти предел функции

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Ответы

Автор ответа: NNNLLL54

Ответ:

$\lim\limits_{x \to \infty}\, \dfrac{3x^2+5x+1}{x^2+4}=\lim\limits_{x \to \infty}\, \dfrac{3+\dfrac{5}{x}+\dfrac{1}{x^2}}{1+\dfrac{4}{x^2}}=\dfrac{3+0+0}{1+0}=3$

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