Question

Помогите!!!Помогите!!!Помогите​

Answer 1

$\it \large \frac{16 {m}^{8} {3}^{3} { \bigg( - c \bigg)}^{3} {n}^{2} }{9} = \frac{16 \times 27 {m}^{8} {\bigg( - c \bigg)}^{3} {n}^{2} }{9} = 48 {m}^{8} {\bigg( - c \bigg)}^{3} {n}^{2} = - 48 {m}^{8} {c}^{3} {n}^{2} ; \Rightarrow \\ \Rightarrow \: \boxed{ \underline {\huge \it \: otvet : \Huge \: - 48}}.$