Предмет: Геометрия, автор: EugeneBog1707

помогите с этим заданием, геометрия.


В равнобедренном треугольнике ABC с основанием BC проведена медиана АМ.
Найдите периметр треугольника ABC, если медиана АМ равена 17,2 см,
а периметр треугольника ABM равен 90,1 см.

Ответы

Автор ответа: Аноним
2

Ответ:

145,8см

Объяснение:

P(∆ABM)=AB+BM+AM;. →

AB+BM=P(∆ABM)-AM

AB+BM=90,1-17,2=72,9см

АВ=ВС; ВМ=МС

Р(∆АВС)=2(АВ+ВМ)=2*72,9=145,8см

Приложения:
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