Question

✓2а-в при а=0,в=0;при а=4,в=7​

Answer 1

Ответ:

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Answer 2

$\displaystyle\bf\\\sqrt{2a-b} \\\\1)\\\\a=0 \ \ ; \ \ b=0\\\\\sqrt{2a-b} =\sqrt{2\cdot 0-0} =\sqrt{0} =0\\\\2)\\\\a=4 \ \ ; \ \ b=7\\\\\sqrt{2a-b} =\sqrt{2\cdot4-7} =\sqrt{8-7} =\sqrt{1} =1$