Question

помогите по алгебре даю 50
баллов умоляю

Answer 1

Ответ:

$\sqrt{ 4x+5} =8 \\4x+5=64\\4x=64-5\\4x=59\\\\x=\dfrac{59}{4}\\x=14\dfrac{3}{4}$

$\sqrt{0.36*49*900} =\sqrt{0.36} \sqrt{49} \sqrt{900} =0.6*7*30=126$

$( 2 \sqrt{ 15} +5) ( 8-\sqrt{15} ) = \\16\sqrt{15} -2*15+40-5\sqrt{15} =11\sqrt{15} +10$

$(3 \sqrt{ 10 \phantom{\tiny{!}}} +4 \sqrt{ 5 \phantom{\tiny{!}}} )( \sqrt{ 10 \phantom{\tiny{!}}} -2 \sqrt{ 5 \phantom{\tiny{!}}} ) =3*10-6\sqrt{50}+4\sqrt{50}-8*5=30-2\sqrt{50}-40=-10-2\sqrt{50} =-10-2*5\sqrt{2} =-10-10\sqrt{2}$

$\sqrt{ 30.6 ^ { 2 } -14.4 ^ { 2 } \phantom{\tiny{!}}} =\sqrt{(30.6-14.4)(30.6+14.4)} =\sqrt{16.2*45} =\sqrt{729} =27$

$\sqrt{ 4h ^ { 24 } g ^ { 2 } z ^ { 16 } \phantom{\tiny{!}}} =2h^{12} |g|z^8$

$\dfrac{ 3 }{ \sqrt{ 57 \phantom{\tiny{!}}} } =\dfrac{3\sqrt{57} }{57} =\dfrac{1}{19}\sqrt{57} =\dfrac{\sqrt{57} }{19}$

$16m-9p = ( \sqrt{ 4m \phantom{\tiny{!}}} ) ^ { 2 } -( \sqrt{ 3p \phantom{\tiny{!}}} ) ^ { 2 } =(\sqrt{4m} +\sqrt{3p} )(\sqrt{4m} -\sqrt{3p} )$

Объяснение: