Question

У простите выражения,пжпжпдпд​

Answer 1

Объяснение:

$( \sqrt{a} - \sqrt{b} )( \sqrt{a} + \sqrt{b} ) = ( \sqrt{a} ) {}^{2} - ( \sqrt{b} ) {}^{2} = a - ( \sqrt{b) } {}^{2} = a - b$

$5 \sqrt{6} (2 \sqrt{6} - \sqrt{2} ) =10\left(\sqrt{6}\right)^{2}-5\sqrt{2}\sqrt{6}=10\times 6-5\sqrt{2}\sqrt{6} =60-5\sqrt{2}\sqrt{6} =60-5\sqrt{2}\sqrt{2}\sqrt{3} =60-5\times 2\sqrt{3} =60-10\sqrt{3}$

$(4 \sqrt{3} + \sqrt{8} )( \sqrt{3} - \sqrt{8} ) =\left(4\sqrt{3}+2\sqrt{2}\right)\left(\sqrt{3}-\sqrt{8}\right) =\left(4\sqrt{3}+2\sqrt{2}\right)\left(\sqrt{3}-2\sqrt{2}\right) =4\left(\sqrt{3}\right)^{2}-8\sqrt{2}\sqrt{3}+2\sqrt{2}\sqrt{3}-4\left(\sqrt{2}\right)^{2} =4\times 3-8\sqrt{2}\sqrt{3}+2\sqrt{2}\sqrt{3}-4\left(\sqrt{2}\right)^{2} =12-8\sqrt{2}\sqrt{3}+2\sqrt{2}\sqrt{3}-4\left(\sqrt{2}\right)^{2} =12-8\sqrt{6}+2\sqrt{2}\sqrt{3}-4\left(\sqrt{2}\right)^{2} =12-8\sqrt{6}+2\sqrt{6}-4\left(\sqrt{2}\right)^{2} =12-6\sqrt{6}-4\left(\sqrt{2}\right)^{2} =12-6\sqrt{6}-4\times 2 =12-6\sqrt{6}-8 =4-6\sqrt{6}$

Answer 2

$( \sqrt{a} - \sqrt{b} )( \sqrt{a} + \sqrt{b} ) = ( \sqrt{a} ) {}^{2} - ( \sqrt{b} ) {}^{2} = a - b$

$5 \sqrt{6} (2 \sqrt{6} - \sqrt{2} ) = 5 \times 6 \times 2 - 5 \times \sqrt{6} \times \sqrt{2} = 60 - 5 \sqrt{12} = 60 - 10 \sqrt{3}$

$(4 \sqrt{3} + \sqrt{8} )( \sqrt{3} - \sqrt{8} ) = 4 \times 3 - 8 \sqrt{6} + 2\sqrt{6} - 8 = 4 - 6 \sqrt{6}$