Question

Найти корни уравнения. 9 класс!!
С подробным решением!!! ​

Answer 1

$\displaystyle\bf\\\frac{x^{2} +12x-13}{x-1} =0\\\\\\\frac{(x-1)(x+13)}{x-1} =0\\\\\\\left \{ {{(x-1)(x+13)=0} \atop {x-1\neq 0}} \right. \\\\\\\left \{ {{x+13=0} \atop {x\neq 1}} \right. \\\\\\\left \{ {{x=-13} \atop {x\neq 1}} \right. \\\\\\Otvet:-13$