Question

розв'язати нерівність 2х^2-3х+1<0. Срочноооо!!!!​

Answer 1

$\displaystyle 2x^2-3x+1<0\\2x^2-x-2x+1<0\\x(2x-1)-(2x-1)<0\\(2x-1)(x-1)<0\\\\ \left \{ {{2x-1<0} \atop {x-1>0}} \right.=\left \{ {{x<\frac{1}{2} } \atop {x>1}} \right. =x \in \phi\\\\ \left \{ {{2x-1>0} \atop {x-1<0}} \right.=\left \{ {{x>\frac{1}{2} } \atop {x<1}} \right.=x \in (\frac{1}{2},1)\\\\ x \in (\frac{1}{2},1)$