Question

упростите
1) n=0,137
2) b=10​

Answer 1

$\displaystyle 1)(m+n)(m-n)+n^2=m^2-n^2+n^2=m^2\\\\ 2)(0,8+0,137)(0,8-0,137)+0,137^2=0,937*0,663+(\frac{137}{1000})^2=0,64\\\\ 3)(a+b)(a+b)-a^2-b^2=(a+b)^2-a^2-b^2=a^2+2ab+b^2-a^2-b^2=2ab\\\\ 4)(0,1+10)(0,1+10)-0,1^2-10^2=10,1*10,1-(\frac{1}{10})^2-100=102,01-\\ \\ \frac{1}{100}-100=\frac{10201}{100}-\frac{1}{100}-100=2$