Question

(4- корень 5) 2 степень

Answer 1

$\displaystyle 1)5\sqrt{48}-2\sqrt{75}=20\sqrt{3}-10\sqrt{3}=10\sqrt{3}\\\\ 2)(3\sqrt{2}+\sqrt{18})\sqrt{2}=(3\sqrt{2}+3\sqrt{2})\sqrt{2}=6\sqrt{2}\sqrt{2}=6*2=12\\\\ 3)(4-\sqrt{5})^2=16-8\sqrt{5}+5=21-8\sqrt{5}\\\\ 4)15\sqrt{2}=\sqrt{225*2}=\sqrt{450}\\\\ 5)-8\sqrt{3}=-\sqrt{64*3}=-\sqrt{192}$