Question

Свойства действий над числами

Answer 1

$\displaystyle 4\frac{6}{8}+3\frac{3}{5}-3\frac{1}{4}+3\frac{2}{5}=4+\frac{6}{8}+3+\frac{3}{5}-(3+\frac{1}{4})+3+\frac{2}{5}=4+\frac{6}{8}+3+\frac{3}{5}-3-\frac{1}{4}+3+\frac{2}{5}=\\ \\ (4+3-3+3)+(\frac{6}{8}+\frac{3}{5}-\frac{1}{4}+\frac{2}{5})=7+\frac{3}{2}=7+1\frac{1}{2}=7+1+\frac{1}{2}=8+\frac{1}{2}=\\ \\ 8\frac{1}{2}=\frac{17}{2}=8,5$