Question

50б алгебра подпишусь за ответ)

Answer 1

Ответ:

$\dfrac{ 2 }{ x ^ { 2 } -9 } - \dfrac{ 1 }{ 2x ^ { 2 } -12x+18 } = \dfrac{ 3 }{ 2x ^ { 2 } +6x } |*2x(x+3)(x-3)^2\\2x(-3+x)*2-x(x+3)=(x-3) ^2*3\\-12x+4x^2-x(x+3)=(x-3) ^2*3\\-12x+4x^2-x^{2} -3x=(x-3) ^2*3\\−12x+3x ^2-3x=(x ^2 -6x+9)*3\\-15x+3x ^2=3x ^2 -18x+27\\-15x=-18x+27\\\\3x=27\\\\x=\dfrac{27}{3} \\\\x=9$

Объяснение:

Answer 2

$\displaystyle \frac{2}{(x-3)(x+3)}-\frac{1}{2(x^2-6x+9)}=\frac{3}{2x(x+3)}\\\\\frac{2}{(x-3)(x+3)}-\frac{1}{2(x-3)^2}=\frac{3}{2x(x+3)}\\\\\frac{2*2x(x-3)-1*x(x+3)-3(x-3)^2}{2x(x-3)^2(x+3)}=0 \\\\x\neq 3; x\neq 0;x\neq -3\\\\4x^2-12x-x^2-3x-3(x^2-6x+9)=0\\\\3x^2-15x-3x^2+18x-27=0\\\\3x-27=0\\\\x=9$