Question

Сократите дробь
$\frac{2b - 6}{ {b}^{2} } - 6b + 9$
​

Answer 1

$\frac{2b - 6}{b^2} - 6b + 9 = \frac{2b-6}{b^2} - \frac{6b^3}{b^2} + \frac{9b^2}{b^2} = \frac{2b-6-6b^3 + 9b^2}{b^2}$