Question

6х²+х-1>0решите неравенство
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Answer 1

$6x {}^{2} + x - 1 > 0 \\ 6x {}^{2} + 3x - 2x - 1 > 0 \\ 3x \times (2x + 1) - (2x + 1) > 0$

X Є

$( - \infty . - \frac{1}{2} ) \: u \: ( \frac{1}{3} . + \infty )$