Question

35б. Упрости выражение hElP mE!1

Answer 1

$\displaystyle\bf\\\frac{(3b^{9} d^{7} )^{2} \cdot(9b^{2} d^{3})^{0} }{(9b^{3}d^{2} )^{2} } =\frac{3^{2} \cdot b^{18} \cdot d^{14}\cdot 1 }{9^{2} \cdot b^{6}\cdot d^{4} } =\frac{b^{12} \cdot d^{10} }{9} =\frac{1}{9} b^{12} d^{10}$