Question

решите уравнение::::​

Answer 1

$\displaystyle \frac{x^2-2x}{x-1}-\frac{2x-1}{1-x}=3,x\neq 1\\\\ \frac{x^2-2x}{x-1}-\frac{2x-1}{-(x-1)}=3\\\\ \frac{x^2-2x}{x-1}+\frac{2x-1}{x-1}=3\\\\ \frac{x^2-2x+2x-1}{x-1}=3\\\\ \frac{(x-1)(x+1)}{x-1}=3\\\\ x+1=3\\x=3-1\\x=2$