Question

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Answer 1

Ответ:

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Объяснение:

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Answer 2

Ответ:

Объяснение:

$\displaystyle\bf\\\frac{\bigg(\dfrac{a}{a-b} +\dfrac{a}{b}\bigg)\bigg(\dfrac{a-b}{a} \bigg)}{\bigg(\dfrac{c}{c-b} +\dfrac{c}{b}\bigg)\bigg(\dfrac{c-b}{c} \bigg)} =\\\\\\=\frac{\dfrac{a}{a-b}\cdot\dfrac{a-b}{a}+\dfrac{a}{b}\cdot \dfrac{a-b}{a}}{\dfrac{c}{c-b}\cdot\dfrac{c-b}{c}+\dfrac{c}{b}\cdot \dfrac{c-b}{c}} =\\\\\\=\frac{1+\dfrac{a-b}{b} }{1+\dfrac{c-b}{b} } =\frac{\dfrac{b+a-b}{b} }{\dfrac{b+c-b}{b} } =\\\\\\=\frac{a}{b} :\frac{c}{b} =\frac{a}{b}\cdot\frac{b}{c} =\frac{a}{c}$