Question

2. Найти похідну функціі
у=cos( 2 - 3х)

Answer 1

$y=cos(2-3x)\\\\y`=(cos(2-3x))`=-sin(2-3x)*(2-3x)`=-sin(2-3x)(0-3)=\\\\-3*(-sin(2-3x))=3sin(2-3x)$

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$cos`x=-sinx\\\\(C)`=0\\\\(kx)`=k$

$(f(g(x))`=f`(g(x))*g`(x)$