Question

помогите пожалуйста. ​

Answer 1

$\displaystyle \frac{8}{x}=x-7,x\neq 0\\\\8=(x-7)x\\8-(x-7)x=0\\8-(x^2-7x)=0\\8-x^2+7x=0\\-x^2+7x+8=0\\x^2-7x-8=0\\x^2+x-8x-8=0\\x(x+1)-8(x+1)=0\\(x+1)(x-8)=0\\x+1=0,x-8=0\\x_1=-1,x_2=8$