Question

2ab/a2-b2+a-b/a+b срочно​

Answer 1

$\frac{2ab}{a^2-b^2}+\frac{a-b}{a+b}=\frac{2ab}{(a-b)(a+b)}+\frac{(a-b)(a-b)}{(a-b)(a+b)}=\frac{2ab+a^2-2ab+b^2}{(a-b)(a+b)}=\frac{a^2+b^2}{a^2-b^2}$

Answer 2

Объяснение:

2ab

+

a+b

a−b

=

(a−b)(a+b)

2ab

+

(a−b)(a+b)

(a−b)(a−b)

=

(a−b)(a+b)

2ab+a

2

−2ab+b

2

=

a

2

−b

2

a

2

+b

2